-16x^2+96x-2=0

Solution for -16x^2+96x-2=0 equation:

-16x^2+96x-2=0

a = -16; b = 96; c = -2;
Δ = b2-4ac
Δ = 962-4·(-16)·(-2)
Δ = 9088
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{9088}=\sqrt{64*142}=\sqrt{64}*\sqrt{142}=8\sqrt{142}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(96)-8\sqrt{142}}{2*-16}=\frac{-96-8\sqrt{142}}{-32}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(96)+8\sqrt{142}}{2*-16}=\frac{-96+8\sqrt{142}}{-32}
$